In a resonance tube experiment, a closed organ pipe of length 120 cm is used. Initially it is completely filled with water. It is vibrated with tuning fork of frequency 340 Hz. To achieve resonance the water level is lowered then (given v air = 340 m/sec., neglect end correction):
Text Solution
Verified by ExpertsCHECK THE SOLUTION
(a, b, c)
x = 
λ =
= 1 m
x =
m = 25 cm

For other resonance position
x = (2n – 1) 
so x = 25, 75, 125 cm.....................
Tube length is only 120 cm so get resonance minimum length of water = 120 – 75 = 45
maximum length = 120 – 25 = 95
Distance between two successes nodes =
= 50
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems